Question

Find the perimeter of a rhombus, the lengths of whose diagonals are $16cm$ and $30cm$.

Answer 1

Perimeter of rhombus is given as

$P=4a$

where

$a=\frac{\sqrt{p^2+q^2}}{2}$

where p and q are diagonals

$a=\frac{\sqrt{{16}^2+{30}^2}}{2}$

$a=\frac{34}{2}$

$a=17$

Now,

Perimeter $P=4\times 17=68cm$