Find the perimeter of a square of area
$256 c m^{2}$

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Solution

Let side of square be 'a'
Area of square $= a^{2}$
Given $a^{2} = 256$
$a = 16$
Perimeter of square $= 4 a = 4 \times 16$
$= 64$ cm.

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Find the perimeter of a square of area 256 cm2

Let side of square be 'a'Area of square =a2Given a2=256a=16Perimeter of square =4a=4×16=64cm.

Find the perimeter of a square of area
$256 c m^{2}$

Let side of square be 'a'
Area of square $= a^{2}$
Given $a^{2} = 256$
$a = 16$
Perimeter of square $= 4 a = 4 \times 16$
$= 64$ cm.