Find the perimeter of a triangle whose sides are $4 c m, 9 c m, 8 c m$

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Solution

Perimeter of triangle:
Here the three sides of Triangle are $a = 4 c m, b = 9 c m c = 8 c m$
Therefore Perimeter of triangle $= a + b + c$
$= 4 + 9 + 8 = 21 c m$
Hence the perimeter of triangle is $21 c m$

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