Find the perimeter of ΔABC if AC || RP?
54cm
According to Basic Proportionality Theorem, if a line is drawn parallel to any sides of the triangle, then it divides other two sides of the triangle proportionally.
Here, RP || AC
∴ BRAR=BPCP
On substituting the values we get:
714=BP10
BP=7×1014=7014=5cm
∴ Perimeter of ΔABC = AB + BC + AC = 18cm + 21cm + 15cm = 54cm