Find the perimeter of the broken part of the wall. Assume that, similar type of lengths are of the same length.
A
70 units
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B
80 units
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C
120 units
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D
150 units
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Solution
The correct option is C 120 units Perimeter of the broken part of the wall
= Sum of all the sides
= 15 + 10 + 5 + 15 + 10 + 5 + 15 + 10 + 5
+ 15 + 10 + 5
= 120 units