Find the perimeter of the given figure :

(32 + 3 $π$ ) cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(36 + 6 $π$ ) cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(46 + 3 $π$ ) cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(26 + 3 $π$ ) cm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
(26 + 3 $π$ ) cm

Join the line AD.

Now,

radius of the circle = $\frac{6}{2}$ = 3cm

Perimeter of the Circle = 2 $π$ r = 6 $π$

Semi-perimeter = 3 $π$

$∴$ Perimeter of the given figure = 10 + 10 + 6 + 3 $π$ = 26 + 3 $π$ cm

Suggest Corrections

Similar questions

\int_{- 3 π}^{3 π} {sin}^{2} θ . {sin}^{2} 2 θ d θ

The value of $\int_{1}^{16} t a n^{- 1} \sqrt{\sqrt{x} - 1} d x$ is

x

x sin \frac{π}{6} {cos}^{2} \frac{π}{4} = \frac{{cot}^{3} \frac{π}{6} sec \frac{π}{6} tan \frac{π}{4}}{{csc}^{2} \frac{π}{4} csc \frac{π}{6}}

sin | x | = | cos x |

[- 3 π, 3 π]

\int_{- 3 π / 2}^{- π / 2} [(x + π)^{3} + {cos}^{2} (x + 3 π)] d x =

Join BYJU'S Learning Program