Find the perimeter of the rectangle whose $l = 42 c m, b = 15 c m$

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Solution

Perimeter of the rectangle = $2 \times (l + b)$
$= 2 \times (42 + 15)$
$= 2 \times 57$
$= 114 c m$

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Find the perimeter of the rectangle whose l=42 cm,b=15 cm

Perimeter of the rectangle = 2×(l+b)=2×(42+15)=2×57=114cm

Find the perimeter of the rectangle whose $l = 42 c m, b = 15 c m$

Perimeter of the rectangle = $2 \times (l + b)$
$= 2 \times (42 + 15)$
$= 2 \times 57$
$= 114 c m$