Find the perimeter of the shaded region, where ADC,AEB and BFC are semicircles on diameters AC,AB and BC respectively.
We know:
Perimeter (circumference of a circle) =2πr
Perimeter of a semi-circle arc =πr
Now,
For the arc ADC, diameter is 2.8+1.4=4.2 cm
radius is 4.22=2.1 cm.
since radius is half of the diameter
Thus, Perimeter of the arc ADC=πr=2.1π cm
Similar way, for the arc AEB, diameter is 2.8 cm
radius is 2.82=1.4 cm.
Thus, Perimeter of the arc AEB=πr=1.4π cm
For the arc BFC, radius is 0.7 cm.
Thus, Perimeter of the arc BFC=πr=0.7π cm
Thus, we have:
Perimeter of the shaded region =2.1π+1.4π+0.7π
=4.2π cm
=4.2×227
=0.6×22
=13.2 cm
Hence, the perimeter of the shaded region is =13.2 cm