You visited us 1 times! Enjoying our articles? Unlock Full Access!

Distance Formula

Find the peri...

Question

Find the perimeter of the triangle with vertices $(- 2, 3), (4, 3),$ and $(6, - 3)$ .

4 \sqrt{11}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

18 \sqrt{10}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10 + 4 \sqrt{5}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

16 + 2 \sqrt{10}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

16 + 3 \sqrt{7}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $16 + 2 \sqrt{10}$
For perimeter, we have to find length of each side of triangle.
The distance between $(- 2, 3)$ and $(4, 3)$ is $\sqrt{36} = 6$
The distance between $(- 2, 3)$ and $(6, - 3)$ is $\sqrt{64 + 36} = 10$
The distance between $(4, 3)$ and $(6, - 3)$ is $\sqrt{4 + 36} = 2 \sqrt{10}$
$∴$ perimeter is $6 + 10 + 2 \sqrt{10} = 16 + 2 \sqrt{10}$ .

Suggest Corrections

Similar questions

\frac{11}{12} \div (\frac{5}{9} \times \frac{18}{25})

(2 \frac{1}{2} \times \frac{8}{10}) \div (1 \frac{1}{2} + \frac{5}{8})

\frac{15}{16}

(\frac{5}{6} - \frac{1}{2}) \div \frac{10}{11}

\frac{9}{8} \div \frac{3}{5}

(\frac{3}{4} + \frac{3}{5})

\frac{2}{5} \div {\frac{1}{5} o f [\frac{3}{4} - \frac{1}{2}] - 1}

(1 \frac{3}{4} \times 3 \frac{1}{7}) - (4 \frac{3}{8} \div 5 \frac{3}{5})

The area of a triangle with sides 10 cm, 7 cm and 7 cm and semi-perimeter 12 cm is

X	$10$	$11$	$12$	$13$	$14$	$15$	$16$	$17$	$18$
f	$2$	$7$	$10$	$12$	$15$	$11$	$10$	$6$	$3$

(0, 7, - 10), (1, 6, - 6)

(4, 9, - 6)

(0, 7, 10), (- 1, 6, 6)

(- 4, 9, 6)

(- 1, 2, 1), (1, - 2, 5), (4, - 7, 8)

(2, - 3, 4)

Join BYJU'S Learning Program