Question

Find the perimeters of (i) ΔABE (ii) the rectangle BCDE in this figure. Whose perimeter is greater?

Answer 1

(i) Perimeter of ΔABE = AB + BE + EA

(ii)

Perimeter of rectangle = 2 (Length + Breadth)

Perimeter of ΔABE =

Changing them to like fractions, we obtain

$$\begin{gathered} \frac{177}{20}=\frac{177\times 3}{20\times 3}=\frac{531}{60} \\ \frac{47}{6}=\frac{47\times 10}{6\times 10}=\frac{470}{60} \end{gathered}$$

As 531 > 470,

$\Rightarrow \frac{177}{20}>\frac{47}{6}$

Perimeter (ΔABE) > Perimeter (BCDE)