Find the perimeters of the triangles whose sides are
$(i) 3 c m, 4 c m, 5 c m (i i) 8 c m, 9 c m, 12 c m (i i i) 3.4 c m$

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Solution

The perimeter of the the triangles whose sides are

i) $3$ cm, $4$ cm, $5$ cm is $3 + 4 + 5 = 12$ cm.

ii) $8$ cm, $9$ cm, $12$ cm is $8 + 9 + 12 = 29$ cm.

iii) $3.4$ cm is $3 \times 3.4 = 10.2$ cm.

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