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Byju's Answer
Standard XII
Mathematics
Domain and Range of Trigonometric Ratios
Find the peri...
Question
Find the period of the following functions.
sin
θ
+
sin
2
θ
cos
θ
+
cos
2
θ
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Solution
sin
θ
+
sin
2
θ
cos
θ
+
cos
2
θ
=
2
sin
3
θ
2
cos
θ
2
2
cos
3
θ
2
cos
θ
2
=
tan
3
θ
2
We know that
tan
x
is periodic with fundamental period
π
.
So,
tan
3
θ
2
is periodic with fundamental period T, such that
3
T
2
=
π
T
=
2
π
3
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Similar questions
Q.
Period of
sin
θ
+
sin
2
θ
cos
θ
+
cos
2
θ
is
Q.
Solve the following equations:
(i)
cos
θ
+
cos
2
θ
+
cos
3
θ
=
0
(ii)
cos
θ
+
cos
3
θ
-
cos
2
θ
=
0
(iii)
sin
θ
+
sin
5
θ
=
sin
3
θ
(iv)
cos
θ
cos
2
θ
cos
3
θ
=
1
4
(v)
cos
θ
+
sin
θ
=
cos
2
θ
+
sin
2
θ
(vi)
sin
θ
+
sin
2
θ
+
sin
3
=
0
(vii)
sin
θ
+
sin
2
θ
+
sin
3
θ
+
sin
4
θ
=
0
(viii)
sin
3
θ
-
sin
θ
=
4
cos
2
θ
-
2
(ix)
sin
2
θ
-
sin
4
θ
+
sin
6
θ
=
0
Q.
Simplify:-
sin
θ
+
cos
θ
sin
θ
−
cos
θ
+
sin
θ
−
cos
θ
sin
θ
+
cos
θ
=
2
sin
2
θ
−
cos
2
θ
Q.
Prove that
sin
θ
−
cos
θ
sin
θ
+
cos
θ
+
sin
θ
+
cos
θ
sin
θ
−
cos
θ
=
2
sin
2
θ
−
cos
2
θ
Q.
Simplify the following expression
sin
2
θ
+
cos
2
θ
sin
θ
+
cos
θ
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Domain and Range of Trigonometric Ratios
Standard XII Mathematics
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