Find the perpendicular distance from $(4, 5)$ to $3 x + 4 y + 5 = 0$

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Solution

Point is $(4, 5)$
Equation is $3 x + 4 y + 5 = 0$
Perpendicular disttance is $\frac{| 3 (4) + 5 (4) + 5 |}{\sqrt{3^{2} + 4^{4}}} \frac{37}{\sqrt{25}} = 7.4$

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