Find the perpendicular distance from $(4, 5)$ to $3 x + 4 y + 5 = 0$

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Solution

Point is $(4, 5)$

Equation is $3 x + 4 y + 5 = 0$

Perpendicular disttance is $= \frac{| 5 |}{\sqrt{3^{2} + 4^{4}}}$

$\Rightarrow \frac{5}{\sqrt{25}} = 1$

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