Question

Find the perpendicular distance from origin to the plane $2x+3y+4z+5=0$

Answer 1

The given plane is $2x+3y+4z+5=0$

The perpendicular distance from origin for $ax+by+cz+d=0$ is given as

$=\frac{|d|}{\sqrt{a^2+b^2+c^2}}$

$=\frac{|5|}{\sqrt{2^2+3^2+4^2}}$

$=\frac{5}{\sqrt{4+9+16}}$

$=\frac{5}{\sqrt{29}}$