Find the perpendicular distance from the origin of the line x + y – 2 = 0 is:

3√3

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5√2

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√2

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√3

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Solution

The correct option is C
√2

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(1, 2)

x - \sqrt{3} y + 4 = 0

Find the perpendicular distance from the origin of the perpendicular from the point (1, 2) upon the straight line $x = \sqrt{3} y + 4 = 0$ .

\sqrt{3} x - y + 5 = 0

4 x + 3 y - 2 = 0

x + 3 y + 6 = 0

3 x - y - 4 z = 0

1

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