Question

Find the perpendicular distance of $(0,0)$ from $3x+4y=12$.

Answer 1

Given the point is $(0,0)$ and the line $3x+4y=12$......(1).

Now the perpendicular distance of $(0,0)$ to (1) is

$\left|\frac{0.3+0.4-12}{\sqrt{3^2+4^2}}\right|=\frac{12}{5}=2.4$ units.