Find the perpendicular distance of a right triangle's hypotenuse from its opposite vertex if the base and attitude of the triangle is 24 cm and 10 cm respectively.

1 cm

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120/13 cm

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14 cm

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32/3 cm

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Insufficient data

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Solution

The correct option is B
120/13 cm

In a right angled triangle,
$p = \frac{P r o d u c t o f s i d e s}{H y p o t e n u s e} = \frac{24 \times 10}{26} = \frac{120}{13} = 9 \frac{3}{13}$

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Find the perpendicular distance of a right triangle's hypotenuse from its opposite vertex if the base and attitude of the triangle is 24 cm and 10 cm respectively.

The correct option is B 120/13 cm In a right angled triangle, p=Product of sides Hypotenuse=24×1026=12013=9313

The correct option is B
120/13 cm

In a right angled triangle,
$p = \frac{P r o d u c t o f s i d e s}{H y p o t e n u s e} = \frac{24 \times 10}{26} = \frac{120}{13} = 9 \frac{3}{13}$