Question

Find the perpendicular distance of the point $(3,4)$ from the line $6x+8y=5$.

Answer 1

The perpendicular distance of the point $(3,4)$ from the line $6x+8y=5$ is

$\left|\frac{6.3+8.4-6}{\sqrt{6^2+8^2}}\right|=\frac{45}{10}=4.5$ units.