Find the perpendicular distance of the point p (5,7) from then axis

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Solution

The distance of a point from the y-axis is given by its x-coordinate

Hence distance of p(5,7) from y-axis =5units

The distance of a point from the x-axis is given by its y-coordinate

Hence distance of p(5,7) from x-axis =5units

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What is the perpendicular distance of the point Q (5,7) from y-axis?

Find the points on the y-axis, which are at a distance of $13$ units each from the point $(- 5, 7) .$

B

(- 5, 7)

P

X

5

X

Y

P

The points on Y-axis at a distance of 13 units from point (–5, 7) are

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