Question

Find the pH of 10^-6 M and 10^-8 M of HCl

Answer 1

$pH$ is calculated as :

$pH=-log\left[H^{+}\right]$
$\left[H^{+}\right]$ is the concentration of H+ ions.

Since HCl is a strong acid, 100% dissociation will occur.

Therefore, for ${10}^{-}6$:

So, $pH=-log{10}^{-}6$
$=>pH=6$

Therefore, for ${10}^{-}8$:

So, $pH=-log{10}^{-}8$
$=>pH=8$