The correct option is A 1
Number of moles of H+ coming from H2SO4 are,
nH+=2×0.05×V
Number of moles of H+ coming from HCl are,
nH+=0.1×V
Here final volume is Vf=V+V=2V L
So, final concentration of H+ will be:
Cf=(2×0.05×V)+(0.1×V)2V =0.1 MpH=− log10[0.1]pH=1