Find the point of intersection of $4 x + 5 y = 12 2 x + y = 0$

(- 2, 4)

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(2, 4)

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(2, - 4)

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(- 2, - 4)

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Solution

The correct option is A $(- 2, 4)$
$4 x + 5 y = 12 2 x + y = 0 y = - 2 x 4 x + 5 (- 2 x) = 12 4 x - 10 x = 12 - 6 x = 12 x = \frac{12}{- 6} = - 2 y = - 2 (- 2) = 4 (x, y) = (- 2, 4)$

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