Question

Find the point of intersection of the curve $y=7x-10-x^2$ with X axis.

Answer 1

The graph of $f\left(x\right)$ is shown in figure

Step:

$y=-(x^2-7x+10)$

put $y=0$ to find out the point of intersection on $X$ axis

Now on factorising we will get

$0=-(x-2)(x-5)$

so $x=2$ and $x=5$

So points of intersection of curve at $X$-axis =$(2,0),(5,0)$