Find the point of intersection of $y = x^{2}$ and $y - 15 x + 56 = 0$

(7, - 8)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(8, 7)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(7, 49)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(- 8, 64)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $(7, 49)$
$y = x^{2} y - 15 x + 56 = 0 x^{2} - 15 x + 56 = 0 x^{2} - 7 x - 8 x + 56 = 0 x (x - 7) - 8 (x - 7) = 0 (x - 7) (x - 8) = 0 x = 7, 8 y = 7^{2}, 8^{2} = 49, 64$

Suggest Corrections

Similar questions

Q. Find the point of intersection of

5 x + 2 y - 7 = 0

3 x - y - 2 = 0

Q. Find the equation of the circle passing through point of intersection of the circle

x^{2} + y^{2} - 8 x - 2 y + 7 = 0

and

x^{2} + y^{2} - 4 x + 10 y + 8 = 0

and its center lie on y-axis.

Equation of smallest circle passing through points of intersection of line $x + y = 1$ & circle $x^{2} + y^{2} = 9$ is

Find the equation of the line passing through the point of intersection of $2 x - 7 y + 11 = 0$ and $x + 3 y - 8 = 0$ and is parallel to (i) x-axis (ii) y-axis.

Q. The equation of the circle which passes through the point of intersection of circles

x^{2} + y^{2} - 8 x - 2 y + 7 = 0

and

x^{2} + y^{2} - 4 x + 10 y + 8 = 0

and having its centre on

y -

axis, will be

Join BYJU'S Learning Program

Find the point of intersection of y=x2 and y−15x+56=0

The correct option is B (7,49)y=x2y−15x+56=0x2−15x+56=0x2−7x−8x+56=0x(x−7)−8(x−7)=0(x−7)(x−8)=0x=7,8y=72,82=49,64

Find the point of intersection of $y = x^{2}$ and $y - 15 x + 56 = 0$

The correct option is B $(7, 49)$
$y = x^{2} y - 15 x + 56 = 0 x^{2} - 15 x + 56 = 0 x^{2} - 7 x - 8 x + 56 = 0 x (x - 7) - 8 (x - 7) = 0 (x - 7) (x - 8) = 0 x = 7, 8 y = 7^{2}, 8^{2} = 49, 64$