Find the point of intersectionof lines $6 x + y = 13 4 x + 3 y = 11$

(2,1)

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(1,2)

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(3,2)

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(2,3)

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Solution

The correct option is D (2,1)
$6 x + y = 13 y = 13 - 6 x 4 x + 3 y = 11 4 x + 3 (13 - 6 x) = 11 4 x + 39 - 18 x = 11 - 14 x = - 28 x = 2 y = 13 - 6 (2) y = 1 (x, y) = (2, 1)$

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