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Question

Find the point on x-axis which is equidistant from points A(−1, 0) and B(5, 0). [CBSE 2013C]

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Solution

Let P(x, 0) be the point on x-axis. Then
AP=BPAP2=BP2x+12+0-02=x-52+0-02x2+2x+1=x2-10x+2512x=24x=2
Hence, x = 2.

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