Question

Find the point on the locus of point that are $3$ units from $x-axis$ and $5$ units from the point $(5,1)$.

Answer 1

Distance formula: $=>\sqrt{\left(\right(x_1-x_2{)}^2+(y_1-y_2{)}^2)}$

Now point is $(5,1)$

and $d=3$

$=>3=\sqrt{\left(\right(x-5{)}^2+(y-1{)}^2)}$

$=>9=(x-5{)}^2+(y-1{)}^2$