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Graph of Quadratic Expression

Find the poin...

Question

Find the point on the straight line 3x+y+4=0 which is equidistance from the points (-5,6)and(3,2)

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Solution

generally if we take means through graph we can tell another point
since it is equidistant point
on a graph u plot these points first .
Then plot another point equidistant from this point
Hope it helpful

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Similar questions

Q. Find the point on the straight line

3 x + y + 4 = 0

which is equidistant from the points

(- 5, 6)

(3, 2)

.

Q. Assertion :Each point on the line

y - x + 12 = 0

is equidistant from the lines

4 y + 3 x - 12 = 0

3 y + 4 x - 24 = 0

Reason: The locus of a point which is equidistant from two given lines is the angular bisector of the two lines.

Q. A point on the straight line,

3 x + 5 y = 15

which is equidistant from the coordinate axes will lie only in:

Q. Find the equation to the straight line which passes through point of intersection of line

2 x + y + 1 = 0

3 x - y + 4 = 0

and is parallel to line

3 x - 2 y = 0

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Q. Find the coordinates of those points on the line

3 x + 2 y = 5

which are equidistant from the lines

4 x + 3 y = 7

2 y - 5 = 0

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Graph of Quadratic Expression

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