Find the point which lies on the perpendicular bisector of the line segment joining the point A(-2,-5) and B(2,5)

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Solution

$D e a r S t u d e n t W e k n o w t h a t, t h e p e r p e n d i c u l a r b i s e c t o r o f t h e a n y l i n e s e g m e n t d i v i d e s t h e l i n e s e g m e n t i n t o t w o e q u a l p a r t s . i . e ., t h e p e r p e d i c u l a r b i s e c t o r o f t h e l i n e s e g m e n t a l w y s p a s s e s t h r o u g h t h e m i d - p o i n t o f t h e l i n e s e g m e n t T h e r e f o r e, M i d - P o i n t o f t h e l i n e s e g m e n t j o i n i n g t h e p o i n t s A (- 2, - 5) a n d B (2, 5) i s = (\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2}) = (\frac{- 2 + 2}{2}, \frac{- 5 + 5}{2}) [x_{1} = - 2, y_{1_{}} = - 5, x_{2} = 2, y_{2} = 5] = (\frac{0}{2}, \frac{0}{2}) = (0, 0) H e n c e, (0, 0) i s t h e r e q u i r e d p o i n t l i e s o n t h e p e r p e n d i c u l a r b i s e c t o r o f t h e l i n e s e g m e n t . R e g a r d s$

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Similar questions

The point which lies on the perpendicular bisector of line segment joining the points A(-2,-5) and B(2,5)is

a) (0,0) b) (0,2) c) (2,0) d) (-2,0)

A (2, 3)

B (6, - 5)

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