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Byju's Answer
Standard XII
Mathematics
Global Maxima
Find the poin...
Question
Find the points of maximum and minimum and the intervals of monotonicity of the following functions.
f
(
x
)
=
(
x
−
2
)
(
8
−
x
)
x
2
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Solution
f
(
x
)
=
−
x
2
+
10
x
−
16
x
2
f
′
(
x
)
=
(
−
2
x
+
10
)
x
2
−
2
x
(
−
x
2
+
10
x
−
16
)
x
4
=
−
10
x
2
+
32
x
x
4
=
0
x
=
0
,
3.2
f
(
0
)
=
∞
is maximum
f
(
3.2
)
=
0.5625
is minimum
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