wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the points on the curve x2+y22x3=0 at which tangents are parallel to the X-axis.

Open in App
Solution

The equation of the given curve is x2+y22x3=0

On differentiating w.r.t. x, we get

2x+2ydydx2=02ydydx=22xdydx=2(1x)2y=1xy

For tangent parallel to X-axis, we must have,dydx=0

1xy=01x=0x=1

Substituting x=1 in Eq. (i), we get

12+y22×13=0y24=0y=±2

Hence, the point at which the tangents are parallel to the X-axis are (1,2) and (1,-2).


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Geometrical Interpretation of a Derivative
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon