Find the position of the point (5,-4) relative to the
hyperbola $9 x^{2} - y^{2} = 1$

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Solution

Since $9 {(5)}^{2} - (- 4^{2}) = 225 - 16 - 1 = 208 > 0,$
So,the point (5,-4) lies inside the hyperbola $9 x^{2} - y^{2} = 1$

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Similar questions

The position of the point (2, 5) relative to the hyperbola $9 x^{2} - y^{2} = 1$

(5, - 4)

9 x^{2} - y^{2} = 1

S = 9 x^{2} - y^{2} - 1

(5, - 4)

S_{1} > 0

9 x^{2} - y^{2} = 1

(5, - 4)

9 y^{2} - x^{2} = 1

(3, - 4)

\frac{x^{2}}{9} - \frac{y^{2}}{16} = 1

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