Find the positive value of x if the distance between the points (x, -1) and (3, 2) is 5.

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Solution

The correct option is B 7
Let P(x, -1) and Q(3, 2) be the given points. Then PQ = 5 (given)
$\sqrt{{(x - 3)}^{2} + {(- 1 - 2)}^{2}} = 5$
$\Rightarrow {(x - 3)}^{2} + 9 = 25$
$\Rightarrow x = 7 o r x = - 1$

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