Question

Find the possible group(s) of exterior angles of a triangle.

• A. ${157}^o,{186}^o,{17}^o$
• B. ${190}^o,{170}^o,0^o$
• C. ${157}^o,6^o,{17}^o$
• D. ${270}^o,{45}^o,{45}^o$

Answer 1

Answer: (A), (D)

${270}^o,{45}^o,{45}^o$

We know that the sum of all the exterior angles of a triangle is equal to ${360}^o$.

Let find out the summation of measure of the given groups of angles.
${157}^o+{186}^o+{17}^o={360}^o$
Hence, this is a possible group of angles.

For the group ${190}^o,{170}^o,0^o,$ one angle is $0^o,$ hence triangle will not be formed.

${157}^o+6^o+{17}^o={180}^o\ne {360}^o$
$\therefore$ This is a wrong option.

${270}^o+{45}^o+{45}^o={360}^o$
Hence, this is also a possible group of angles.