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Question

Find the possible values of a such that f(x)=e2x(a+1)ex+2x is monoatomically increasing for xR.

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Solution

f(x)=e2x(a+1)ex+2x
f(x)=2e2x(a+1)ex+2
Now, 2e2x(a+1)ex+20 for all xR
2(ex+1ex)(a+1)0 for all xR
a+124( ex+1ex has minimum value 2)

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