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Question

Find the possible values of sinhx for which
12cosh2x+7sinhx=24
(You may find the identity cosh2xsinh2x=1 useful)
Hence find the possible values of x, leaving your answers as natural logarithms

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Solution

Using the identity cosh2xsinh2x=1

Let sinhx=t

12(1+t2)+7t=24

12t2+7t12=0

(3t+4)(4t3)=0

t=43 or t=34

Case 1: t=43

sinhx=43

exex2=43

(3ex1)(ex+3)=0

ex=13 (as ex is always positive)

x=13ln3

Case 2: t=34

(2ex+1)(ex2)=0

ex=2

x=ln2

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