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Question

Find the potential drop across 4μF capacitor and 6Ω resistor in figure.


A

0V,0V

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B

0V,3V

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C

0V,2V

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D

2V,0V

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Solution

The correct option is D

2V,0V


Step 1: Find the current in the circuit

We know a capacitor draws no current.

Therefore, no current flows through the branch containing the capacitor.

The total resistance of the circuit, excluding the branch containing the capacitor,

R=2+4R=6Ω

Current,

I=VRI=36I=12

Step 2: Finding the potential drop across 4μF capacitor

The potential drop across 4Ω resistor,

V4Ω=I×4V4Ω=12×4I=12V4Ω=2V

The potential drop across 4Ω resistor is 2V

Since no current flows through the branch containing the capacitor,

The whole potential drop occurs across the 4μF capacitor.

Since it is a parallel combination,

The potential drop across the 4μF capacitor = The potential drop across the 4Ω resistor

Therefore, the potential drop across the 4μF capacitor is 2V

Step 3: Find the potential drop across 6Ω resistor

Since no current flows through the branch containing the capacitor,

The potential drop across the 6Ω resistor, V6Ω=0×6=0V

Therefore, the potential drop across the 6Ω resistor is 0V

So, the potential drop across the 4μF capacitor is 2V and the potential drop across the 6Ω resistor is 0V.

hence, option D is the correct answer.


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