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Question
Find the potential V of an electrostatic field →E=a(y^i+x^j), where a is a constant.
Find the potential V of an electrostatic field →E=a(y^i+x^j), where a is a constant.
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Solution
The correct option is B −axy+C
dV=−^E.^dr
dV=−a(y^i+x^j).(dx^i+dy^j)
∫dV=−a∫(ydx+xdy)
∫dV=−a∫d(xy)
∴V=−axy+C
dV=−^E.^dr
dV=−a(y^i+x^j).(dx^i+dy^j)
∫dV=−a∫(ydx+xdy)
∫dV=−a∫d(xy)
∴V=−axy+C
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