Question

Find the predecessor of each of the numbers given below. Then, arrange the predecessors in descending order.

$8,712;6,456;4,013;1,051;706;6,019;4,038;2,080$

Answer 1

Predecessor of a number is obtained by subtracting $1$from the given number.

Predecessor of $8712=8712-1=8711$

Predecessor of $6456=6456-1=6455$

Predecessor of $4013=4013-1=4012$

Predecessor of $1051=1051-1=1050$

Predecessor of $706=706-1=705$

Predecessor of $6019=6019-1=6018$

Predecessor of $4038=4038-1=4037$

Predecessor of $2080=2080-1=2079$

In order to compare numbers, the number with more digits is always greater than the number with less number of digits and if the two numbers have same number of digits, we compare from the left most place until there are unequal digits.

Arranging above predecessors in descending order, we get $8711>6455>6018>4037>4012>2079>1050>705$

Hence, descending order of above predecessors are $8711>6455>6018>4037>4012>2079>1050>705$.