CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

Find the principal and general solutions of the following equation:

secx=2

A
Principal solution =π6,5π6 and General solution =nπ±π6,nZ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Principal solution =π3,5π3 and General solution =nπ±π3,nZ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Principal solution =π6,5π6 and General solution =2nπ±π6,nZ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Principal solution =π3,5π3 and General solution =2nπ±π3,nZ
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D Principal solution =π3,5π3 and General solution =2nπ±π3,nZ
secx=2
1cosx=2
cosx=1/2
we know that cos600=1/2
cos is positive in I & IV quadrant. so, principal values x=π3 and x=5π3
For general solution-
let cosx=cosy(1)
given cosx=1/2(2)
from eq (1) & (2)
cosy=1/2
cosy=cosπ3
y=π3
cosx=cosy
General solution is
x=2nπ±y,nz
put y=π3
x=2nπ±π3,nz

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
General Solutions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon