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Question

Find the principal solution of 3cos2θcos 2θ=1


A

θ=0

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B

θ=π2

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C

θ=π2

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D

θ=π

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Solution

The correct option is C

θ=π2


3cos2θcos 2θ=13cos2θ(2cos2θ1)=1cos2θ=0cosθ=0θ=π2


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