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Question

Find the principal solutions of 2sin2xsin x1=0


A

x=π6

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B

x=π2

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C

x=π6

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D

x=π2

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Solution

The correct options are
B

x=π2


C

x=π6


2sin2xsin x1=0Let sin x=t2t2t1=0t=1±14×2×(1)2×2t=1±34t=1 or t=12sin x=1 or sin x=12x=π2 or x=π6


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