Find the principal values of the following questions:
cos−1(−1√2)
Let cos−1(−1√2)=θ⇒cos θ=−1√2
We know that the range of principal value of cos−1θ is [0,π]
∴ cosθ=−1√2=−cosπ4=cos(π−π4) [∵ cos(π−θ)=−cosθ]
⇒ θ=3π4, where θϵ[0,π] ⇒cos−1(−1√2)=3π4
Hence, the principal value of cos−1(−1√2) is 3π4