Find the principal when simple interest 16% per annum for 212years is ₹3840.
Let the principal be P.
Time (T) = 212years=52years
Rate of interest (R) = 16%perannum
Simple interest (I) = ₹3840
P×R×T100=₹3840
P×16×52100=₹3840
P=3840×100×216×5
P=16×24×10×100×216×5
P=24×2×100×2
P=₹9600
Hence, Principal is ₹9600
Find the simple interest, when:(i) Principal =Rs.2000, Rate of Interest =5% per annum and Time =5 years.(ii) Principal =Rs.500, Rate of Interest =12.5% per annum and Time =4 years.(iii) Principal =Rs.4500, Rate of Interest =4% per annum and Time =6 months.(iv) Principal =Rs.12000, Rate of Interest =18% per annum and Time =4 months.(v) Principal =Rs.1000, Rate of Interest =10% per annum and Time =73 days.
A person lent out 16000 rupees on simple interest and the same sum on compound interest for 2years at 12 1/2%per annum. Find the ratio of the amounts received by him as interests after two years.