Find the principal when the following are given for simple interest
$I = R s 192$ Rate= $6$ per annum Time= $4$ years

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Solution

As we know that,

$S . I . = \frac{P \times R \times t}{100}$

Given:-

$S . I . = R s . 192$

$R = 6 %$

$t = 4 years$

$P = ?$

Therefore,

$192 = \frac{P \times 6 \times 4}{100}$

$\Rightarrow P = \frac{19200}{24} = R s . 800$

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(ii) Principal $= R s .500$ , Rate of Interest $= 12.5 %$ per annum and Time $= 4$ years.
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Q. Find the principal, when the following are given.

I =

Rs.

192

Rate

=

6 %

per annum
Time

=

4

years

What will principal amount be $R s . 496$ in $6$ years at the rate of simple interest of $4 %$ per annum?

Q. Find the principal when the following are given.

I = R s 20

Rate=

2

per annum Time=

2

years

Q. Find the compound interest at the rate of

10 %

per annum for four years on the principal which in four years at the rate of

4 %

per annum gives Rs 1600 as simple interest. [4 MARKS]

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Find the principal when the following are given for simple interestI=Rs 192 Rate=6 per annum Time=4 years

As we know that,S.I.=P×R×t100Given:-S.I.=Rs.192R=6%t=4 yearsP=?Therefore,192=P×6×4100⇒P=1920024=Rs.800

Find the principal when the following are given for simple interest
$I = R s 192$ Rate= $6$ per annum Time= $4$ years

As we know that,

$S . I . = \frac{P \times R \times t}{100}$

Given:-

$S . I . = R s . 192$

$R = 6 %$

$t = 4 years$

$P = ?$

Therefore,

$192 = \frac{P \times 6 \times 4}{100}$

$\Rightarrow P = \frac{19200}{24} = R s . 800$