Question

Find the probability of getting $2$ heads and $2$ tails from tossing of $4$ coins.

• A. $\frac{3}{8}$
• B. $\frac{2}{5}$
• C. $\frac{1}{10}$
• D. $\frac{4}{5}$

Answer 1

The correct option is A $\frac{3}{8}$

Assuming a fair coin, independent tosses and 0 chance of landing on the edge. There are $\times 4=16$ possible results: ${}^4{C}_2=6$ of them have $2$ heads. Since all $16$ are equally likely, the chance is $\frac{6}{16}=\frac{3}{8}$