Question

Find the probability of getting $53$ fridays in a leap year.

• A. $\frac{1}{7}$
• B. $\frac{2}{7}$
• C. $\frac{3}{7}$
• D. $\frac{4}{7}$

Answer 1

Answer: (B)

$\frac{2}{7}$

There are 52 complete weeks and 366 days in a leap year.

there will be 2 extra days which can be any day of the week.

For getting 53 Fridays, those days must be either fri sat or thur fri.

Total possibilities are 7.

Thus, probability = $\frac{2}{7}$