Find the probability of getting 9 cards of the same suit in one hand at a game of bridge?

Open in App

Solution

4 suits
13c9 ways of getting 9 cards from a suit
39c4 ways of getting 4 cards from other suits

52c13 total ways of getting a hand

reqd. probability
= 413c939c4 / 52c13
≈ 1 in 2700

Suggest Corrections

Similar questions

Q. In bridge game of playing cards,

4

players are distributed one card each by turn so that each player gets

13

cards. Find out the probability of a specified player getting a black ace and a king.

Q. Four cards are drawn at a time from a pack of

52

playing cards. Find the probability of getting all the

4

cards of the same suit.

Q. Four cards are drawn at random from a pack of

52

playing cards. The probability of getting all the four cards of the same suit is

In a deck of playing cards, 2 new suits are introduced which are red and black in color respectively. If the number and types of cards in the new suits are same as the standard suits. Find the probability that I will get a face card on a random draw of 1 card. Also find the probability if the new suits were not introduced

Q. Two cards are drawn at random from a pack of cards. Find the probability that a)the cards belongs to same suit. b)cards belong to different suit.

Join BYJU'S Learning Program

Find the probability of getting 9 cards of the same suit in one hand at a game of bridge?

4 suits 13c9 ways of getting 9 cards from a suit 39c4 ways of getting 4 cards from other suits 52c13 total ways of getting a hand reqd. probability = 4*13c9*39c4 / 52c13 ≈ 1 in 2700

4 suits
13c9 ways of getting 9 cards from a suit
39c4 ways of getting 4 cards from other suits

52c13 total ways of getting a hand

reqd. probability
= 413c939c4 / 52c13
≈ 1 in 2700