Question

Find the probability of getting a doublet in a throw of a pair of dice.

Answer 1

Dear Student
Doublet in a pair of dice can be:-
(1,1) (2,2) (3,3) (4,4) (5,5) (6,6)

and total no. of outcomes when two dice are thrown are:-
(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)
(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)
(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)
(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)
(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)
(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)

Total outcome =36
Outcome of doublet=6

Probability = $\frac{numberofdoublet}{totaloutcome}=\frac{6}{36}=\frac{1}{6}$


Regards